13514117 has 2 divisors, whose sum is σ = 13514118. Its totient is φ = 13514116.

The previous prime is 13514107. The next prime is 13514119. The reversal of 13514117 is 71141531.

It is a happy number.

13514117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13315201 + 198916 = 3649^2 + 446^2 .

It is an emirp because it is prime and its reverse (71141531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13514117 is a prime.

Together with 13514119, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13514092 and 13514101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13514119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6757058 + 6757059.

It is an arithmetic number, because the mean of its divisors is an integer number (6757059).

Almost surely, 2^13514117 is an apocalyptic number.

It is an amenable number.

13514117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13514117 is an equidigital number, since it uses as much as digits as its factorization.

13514117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 420, while the sum is 23.

The square root of 13514117 is about 3676.1551925891. The cubic root of 13514117 is about 238.1931264397.

Adding to 13514117 its reverse (71141531), we get a palindrome (84655648).

It can be divided in two parts, 13514 and 117, that added together give a palindrome (13631).

The spelling of 13514117 in words is "thirteen million, five hundred fourteen thousand, one hundred seventeen".