Base | Representation |
---|---|
bin | 10011101100101010001… |
… | …000001111001000011101 |
3 | 11210101221012122220112010 |
4 | 103230222020033020131 |
5 | 134134204101003240 |
6 | 2513502314301433 |
7 | 166540000624434 |
oct | 23545210171035 |
9 | 4711835586463 |
10 | 1353621500445 |
11 | 482082059115 |
12 | 19a411127879 |
13 | 9a852234626 |
14 | 49730c6411b |
15 | 253266c7280 |
hex | 13b2a20f21d |
1353621500445 has 64 divisors (see below), whose sum is σ = 2282760290304. Its totient is φ = 683581282560.
The previous prime is 1353621500419. The next prime is 1353621500563. The reversal of 1353621500445 is 5440051263531.
It is a happy number.
It is not a de Polignac number, because 1353621500445 - 27 = 1353621500317 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 124971180 + ... + 124982010.
It is an arithmetic number, because the mean of its divisors is an integer number (35668129536).
Almost surely, 21353621500445 is an apocalyptic number.
1353621500445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1353621500445 is a deficient number, since it is larger than the sum of its proper divisors (929138789859).
1353621500445 is a wasteful number, since it uses less digits than its factorization.
1353621500445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14482.
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 1353621500445 its reverse (5440051263531), we get a palindrome (6793672763976).
The spelling of 1353621500445 in words is "one trillion, three hundred fifty-three billion, six hundred twenty-one million, five hundred thousand, four hundred forty-five".
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