Base | Representation |
---|---|
bin | 10011110011110001011… |
… | …110001011011011000100 |
3 | 11211010122121111212222202 |
4 | 103303301132023123010 |
5 | 134300330241320300 |
6 | 2521204333014032 |
7 | 200230212420602 |
oct | 23636136133304 |
9 | 4733577455882 |
10 | 1361260885700 |
11 | 485342311351 |
12 | 19b9a3624318 |
13 | 9b49bb45c31 |
14 | 49c5769a872 |
15 | 256221ddad5 |
hex | 13cf178b6c4 |
1361260885700 has 72 divisors (see below), whose sum is σ = 3154051336128. Its totient is φ = 508717883520.
The previous prime is 1361260885693. The next prime is 1361260885793. The reversal of 1361260885700 is 75880621631.
It is a super-3 number, since 3×13612608857003 (a number of 37 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6783107 + ... + 6980906.
Almost surely, 21361260885700 is an apocalyptic number.
1361260885700 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1361260885700 is an abundant number, since it is smaller than the sum of its proper divisors (1792790450428).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1361260885700 is a wasteful number, since it uses less digits than its factorization.
1361260885700 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13764093 (or 13764086 counting only the distinct ones).
The product of its (nonzero) digits is 483840, while the sum is 47.
The spelling of 1361260885700 in words is "one trillion, three hundred sixty-one billion, two hundred sixty million, eight hundred eighty-five thousand, seven hundred".
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