13621125245640 has 128 divisors (see below), whose sum is σ = 44581004104320. Its totient is φ = 3301885337600.

The previous prime is 13621125245639. The next prime is 13621125245657. The reversal of 13621125245640 is 4654252112631.

It is a super-2 number, since 2×13621125245640² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13621125245592 and 13621125245601.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 21441862 + ... + 22067978.

It is an arithmetic number, because the mean of its divisors is an integer number (348289094565).

Almost surely, 2^{13621125245640} is an apocalyptic number.

13621125245640 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13621125245640 is an abundant number, since it is smaller than the sum of its proper divisors (30959878858680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13621125245640 is a wasteful number, since it uses less digits than its factorization.

13621125245640 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 642623 (or 642619 counting only the distinct ones).

The product of its (nonzero) digits is 345600, while the sum is 42.

The spelling of 13621125245640 in words is "thirteen trillion, six hundred twenty-one billion, one hundred twenty-five million, two hundred forty-five thousand, six hundred forty".