Base | Representation |
---|---|
bin | 1100101101010011110001… |
… | …0011010100001000110000 |
3 | 1211110202120100200011200100 |
4 | 3023110330103110020300 |
5 | 3312411230304410224 |
6 | 45414521342352400 |
7 | 2641324401006360 |
oct | 313247423241060 |
9 | 54422510604610 |
10 | 13972540310064 |
11 | 44a77a2818166 |
12 | 1697b7b58b700 |
13 | 7a47b2c62ccb |
14 | 3643bb5689a0 |
15 | 1936d0313ac9 |
hex | cb53c4d4230 |
13972540310064 has 60 divisors (see below), whose sum is σ = 44689950360016. Its totient is φ = 3992154374016.
The previous prime is 13972540309997. The next prime is 13972540310081. The reversal of 13972540310064 is 46001304527931.
13972540310064 is a `hidden beast` number, since 1 + 3 + 9 + 72 + 540 + 31 + 0 + 0 + 6 + 4 = 666.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6930822559 + ... + 6930824574.
Almost surely, 213972540310064 is an apocalyptic number.
13972540310064 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13972540310064 is an abundant number, since it is smaller than the sum of its proper divisors (30717410049952).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13972540310064 is a wasteful number, since it uses less digits than its factorization.
13972540310064 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13861647154 (or 13861647145 counting only the distinct ones).
The product of its (nonzero) digits is 544320, while the sum is 45.
Adding to 13972540310064 its reverse (46001304527931), we get a palindrome (59973844837995).
The spelling of 13972540310064 in words is "thirteen trillion, nine hundred seventy-two billion, five hundred forty million, three hundred ten thousand, sixty-four".
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