Base | Representation |
---|---|
bin | 11111111001110101100110… |
… | …110110011001101011010000 |
3 | 200101210212222202110112011002 |
4 | 133321311212312121223100 |
5 | 121342401044101130000 |
6 | 1214231211200441132 |
7 | 41361232011250412 |
oct | 3771654666315320 |
9 | 611725882415132 |
10 | 140314012130000 |
11 | 40787924961175 |
12 | 138a19669191a8 |
13 | 603a729507397 |
14 | 269133d3829b2 |
15 | 1134d51dc78d5 |
hex | 7f9d66d99ad0 |
140314012130000 has 100 divisors (see below), whose sum is σ = 339734244991680. Its totient is φ = 56122302192000.
The previous prime is 140314012129937. The next prime is 140314012130003. The reversal of 140314012130000 is 31210413041.
It is a tau number, because it is divible by the number of its divisors (100).
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140314012130003) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 173185847 + ... + 173994153.
Almost surely, 2140314012130000 is an apocalyptic number.
140314012130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 140314012130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (169867122495840).
140314012130000 is an abundant number, since it is smaller than the sum of its proper divisors (199420232861680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
140314012130000 is an equidigital number, since it uses as much as digits as its factorization.
140314012130000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 825694 (or 825673 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 140314012130000 its reverse (31210413041), we get a palindrome (140345222543041).
The spelling of 140314012130000 in words is "one hundred forty trillion, three hundred fourteen billion, twelve million, one hundred thirty thousand".
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