1403200023040 has 40 divisors (see below), whose sum is σ = 3364391311380. Its totient is φ = 561280008192.

The previous prime is 1403200023023. The next prime is 1403200023041. The reversal of 1403200023040 is 403200023041.

It can be written as a sum of positive squares in 2 ways, for example, as 1381583966464 + 21616056576 = 1175408^2 + 147024^2 .

It is a tau number, because it is divible by the number of its divisors (40).

It is a junction number, because it is equal to n+sod(n) for n = 1403200022999 and 1403200023017.

It is not an unprimeable number, because it can be changed into a prime (1403200023041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 274059945 + ... + 274065064.

Almost surely, 2^{1403200023040} is an apocalyptic number.

1403200023040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1403200023040 is an abundant number, since it is smaller than the sum of its proper divisors (1961191288340).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1403200023040 is an frugal number, since it uses more digits than its factorization.

1403200023040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 548125032 (or 548125016 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 19.

Adding to 1403200023040 its reverse (403200023041), we get a palindrome (1806400046081).

Subtracting from 1403200023040 its reverse (403200023041), we obtain a palindrome (999999999999).

The spelling of 1403200023040 in words is "one trillion, four hundred three billion, two hundred million, twenty-three thousand, forty".