Base | Representation |
---|---|
bin | 100000000011110101100110… |
… | …011101010001011100001111 |
3 | 200111020120202002021000220022 |
4 | 200003311212131101130033 |
5 | 121440130424234410111 |
6 | 1215515020204212355 |
7 | 41462000121354215 |
oct | 4003654635213417 |
9 | 614216662230808 |
10 | 141001200310031 |
11 | 40a223007548a6 |
12 | 13992b8883a0bb |
13 | 608a48257b859 |
14 | 26b66ccd04cb5 |
15 | 1147b713002db |
hex | 803d6675170f |
141001200310031 has 4 divisors (see below), whose sum is σ = 141014078319000. Its totient is φ = 140988322301064.
The previous prime is 141001200309973. The next prime is 141001200310057. The reversal of 141001200310031 is 130013002100141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141001200310031 - 230 = 141000126568207 is a prime.
It is a super-2 number, since 2×1410012003100312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 141001200309991 and 141001200310009.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141001200310331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6438988061 + ... + 6439009958.
It is an arithmetic number, because the mean of its divisors is an integer number (35253519579750).
Almost surely, 2141001200310031 is an apocalyptic number.
141001200310031 is a deficient number, since it is larger than the sum of its proper divisors (12878008969).
141001200310031 is a wasteful number, since it uses less digits than its factorization.
141001200310031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12878008968.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 141001200310031 its reverse (130013002100141), we get a palindrome (271014202410172).
The spelling of 141001200310031 in words is "one hundred forty-one trillion, one billion, two hundred million, three hundred ten thousand, thirty-one".
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