141114201341130 has 48 divisors (see below), whose sum is σ = 382848963644160. Its totient is φ = 35994347008224.

The previous prime is 141114201341129. The next prime is 141114201341159. The reversal of 141114201341130 is 31143102411141.

141114201341130 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 14 + 201 + 3 + 411 + 30 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 141114201341094 and 141114201341103.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 34085553810 + ... + 34085557949.

It is an arithmetic number, because the mean of its divisors is an integer number (7976020075920).

Almost surely, 2^{141114201341130} is an apocalyptic number.

141114201341130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

141114201341130 is an abundant number, since it is smaller than the sum of its proper divisors (241734762303030).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141114201341130 is a wasteful number, since it uses less digits than its factorization.

141114201341130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68171111795 (or 68171111792 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 27.

Adding to 141114201341130 its reverse (31143102411141), we get a palindrome (172257303752271).

The spelling of 141114201341130 in words is "one hundred forty-one trillion, one hundred fourteen billion, two hundred one million, three hundred forty-one thousand, one hundred thirty".