141123204013545 has 40 divisors (see below), whose sum is σ = 272436134026056. Its totient is φ = 69476038896384.

The previous prime is 141123204013513. The next prime is 141123204013549. The reversal of 141123204013545 is 545310402321141.

141123204013545 is a `hidden beast` number, since 1 + 4 + 11 + 232 + 0 + 401 + 3 + 5 + 4 + 5 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 27755395818921 + 113367808194624 = 5268339^2 + 10647432^2 .

It is not a de Polignac number, because 141123204013545 - 2⁵ = 141123204013513 is a prime.

It is a super-2 number, since 2×141123204013545² (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (141123204013549) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 13402008412 + ... + 13402018941.

Almost surely, 2^{141123204013545} is an apocalyptic number.

141123204013545 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

141123204013545 is a deficient number, since it is larger than the sum of its proper divisors (131312930012511).

141123204013545 is a wasteful number, since it uses less digits than its factorization.

141123204013545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26804027383 (or 26804027374 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 36.

Adding to 141123204013545 its reverse (545310402321141), we get a palindrome (686433606334686).

The spelling of 141123204013545 in words is "one hundred forty-one trillion, one hundred twenty-three billion, two hundred four million, thirteen thousand, five hundred forty-five".