141131212210120 has 128 divisors (see below), whose sum is σ = 376703458911360. Its totient is φ = 46996142837760.

The previous prime is 141131212210073. The next prime is 141131212210207. The reversal of 141131212210120 is 21012212131141.

141131212210120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a junction number, because it is equal to n+sod(n) for n = 141131212210091 and 141131212210100.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 254693634 + ... + 255247153.

It is an arithmetic number, because the mean of its divisors is an integer number (2942995772745).

Almost surely, 2^{141131212210120} is an apocalyptic number.

141131212210120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

141131212210120 is an abundant number, since it is smaller than the sum of its proper divisors (235572246701240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141131212210120 is a wasteful number, since it uses less digits than its factorization.

141131212210120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 509940863 (or 509940859 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 141131212210120 its reverse (21012212131141), we get a palindrome (162143424341261).

The spelling of 141131212210120 in words is "one hundred forty-one trillion, one hundred thirty-one billion, two hundred twelve million, two hundred ten thousand, one hundred twenty".