Base | Representation |
---|---|
bin | 100000000111000100001101… |
… | …101111011100100011010100 |
3 | 200112000210101011222012101220 |
4 | 200013010031233130203110 |
5 | 122002244301322420200 |
6 | 1220204550145250340 |
7 | 41514012556335144 |
oct | 4007041557344324 |
9 | 615023334865356 |
10 | 141223050201300 |
11 | 40aa83a5185781 |
12 | 13a09b819339b0 |
13 | 60a53795b3472 |
14 | 26c3336c50924 |
15 | 114d807b014a0 |
hex | 80710dbdc8d4 |
141223050201300 has 72 divisors (see below), whose sum is σ = 408622308123456. Its totient is φ = 37657917884160.
The previous prime is 141223050201253. The next prime is 141223050201371. The reversal of 141223050201300 is 3102050322141.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2510392 + ... + 16992591.
It is an arithmetic number, because the mean of its divisors is an integer number (5675309835048).
Almost surely, 2141223050201300 is an apocalyptic number.
141223050201300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
141223050201300 is an abundant number, since it is smaller than the sum of its proper divisors (267399257922156).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141223050201300 is a wasteful number, since it uses less digits than its factorization.
141223050201300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19527137 (or 19527130 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 24.
The spelling of 141223050201300 in words is "one hundred forty-one trillion, two hundred twenty-three billion, fifty million, two hundred one thousand, three hundred".
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