Base | Representation |
---|---|
bin | 1100110110001100111001… |
… | …0010111100101101011000 |
3 | 1212000100220101110111221212 |
4 | 3031203032102330231120 |
5 | 3322412120231334000 |
6 | 50013025055122252 |
7 | 2655343303034012 |
oct | 315431622745530 |
9 | 55010811414855 |
10 | 14125313543000 |
11 | 455656a281260 |
12 | 17016b6b13388 |
13 | 7b601bc2a0aa |
14 | 36b9513731b2 |
15 | 1976725e1c35 |
hex | cd8ce4bcb58 |
14125313543000 has 64 divisors (see below), whose sum is σ = 36058073145120. Its totient is φ = 5136477648000.
The previous prime is 14125313542997. The next prime is 14125313543017. The reversal of 14125313543000 is 34531352141.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 642048707 + ... + 642070706.
Almost surely, 214125313543000 is an apocalyptic number.
14125313543000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14125313543000 is an abundant number, since it is smaller than the sum of its proper divisors (21932759602120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14125313543000 is a wasteful number, since it uses less digits than its factorization.
14125313543000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1284119445 (or 1284119431 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 14125313543000 its reverse (34531352141), we get a palindrome (14159844895141).
The spelling of 14125313543000 in words is "fourteen trillion, one hundred twenty-five billion, three hundred thirteen million, five hundred forty-three thousand".
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