Base | Representation |
---|---|
bin | 1100110110011110011110… |
… | …1111001001101101111100 |
3 | 1212000211002110100100112110 |
4 | 3031213213233021231330 |
5 | 3323001303021142022 |
6 | 50015125411334020 |
7 | 2655601306430403 |
oct | 315474757115574 |
9 | 55024073310473 |
10 | 14130035334012 |
11 | 4558572638784 |
12 | 17025b42b1310 |
13 | 7b65c224a580 |
14 | 36bc7c4d463a |
15 | 19784bde100c |
hex | cd9e7bc9b7c |
14130035334012 has 48 divisors (see below), whose sum is σ = 36331969224320. Its totient is φ = 4246593801408.
The previous prime is 14130035334001. The next prime is 14130035334013. The reversal of 14130035334012 is 21043353003141.
It is a happy number.
It is a super-2 number, since 2×141300353340122 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14130035334013) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1053215962 + ... + 1053229377.
Almost surely, 214130035334012 is an apocalyptic number.
14130035334012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
14130035334012 is an abundant number, since it is smaller than the sum of its proper divisors (22201933890308).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14130035334012 is a wasteful number, since it uses less digits than its factorization.
14130035334012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2106445402 (or 2106445400 counting only the distinct ones).
The product of its (nonzero) digits is 12960, while the sum is 30.
Adding to 14130035334012 its reverse (21043353003141), we get a palindrome (35173388337153).
The spelling of 14130035334012 in words is "fourteen trillion, one hundred thirty billion, thirty-five million, three hundred thirty-four thousand, twelve".
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