Base | Representation |
---|---|
bin | 10100101010101101100… |
… | …100111000100110001111 |
3 | 12000202220202110012121100 |
4 | 110222231210320212033 |
5 | 141232133320210210 |
6 | 3004242055034143 |
7 | 204416103106140 |
oct | 24525544704617 |
9 | 5022822405540 |
10 | 1420251335055 |
11 | 4a8363942033 |
12 | 1ab30736b953 |
13 | a3c103a0a77 |
14 | 4ca52037ac7 |
15 | 26e25ec55c0 |
hex | 14aad93898f |
1420251335055 has 24 divisors (see below), whose sum is σ = 2813450264352. Its totient is φ = 649257753024.
The previous prime is 1420251335051. The next prime is 1420251335059. The reversal of 1420251335055 is 5505331520241.
1420251335055 is a `hidden beast` number, since 1 + 4 + 2 + 0 + 251 + 3 + 350 + 55 = 666.
It is an interprime number because it is at equal distance from previous prime (1420251335051) and next prime (1420251335059).
It is not a de Polignac number, because 1420251335055 - 22 = 1420251335051 is a prime.
It is a super-2 number, since 2×14202513350552 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1420251335051) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2254366884 + ... + 2254367513.
It is an arithmetic number, because the mean of its divisors is an integer number (117227094348).
Almost surely, 21420251335055 is an apocalyptic number.
1420251335055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1420251335055 is a deficient number, since it is larger than the sum of its proper divisors (1393198929297).
1420251335055 is a wasteful number, since it uses less digits than its factorization.
1420251335055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4508734415 (or 4508734412 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 36.
Adding to 1420251335055 its reverse (5505331520241), we get a palindrome (6925582855296).
The spelling of 1420251335055 in words is "one trillion, four hundred twenty billion, two hundred fifty-one million, three hundred thirty-five thousand, fifty-five".
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