Base | Representation |
---|---|
bin | 100000010100000001010001… |
… | …011000101010100101001010 |
3 | 200122011220010021100121102010 |
4 | 200110001101120222211022 |
5 | 122111340410241413120 |
6 | 1222125531145120350 |
7 | 41635225436041101 |
oct | 4024012130524512 |
9 | 618156107317363 |
10 | 142113243310410 |
11 | 41310984a67269 |
12 | 13b325b97890b6 |
13 | 613b2b5395a48 |
14 | 27144639c1038 |
15 | 1166a591b77e0 |
hex | 81405162a94a |
142113243310410 has 128 divisors (see below), whose sum is σ = 358729641492480. Its totient is φ = 35961113776896.
The previous prime is 142113243310397. The next prime is 142113243310427. The reversal of 142113243310410 is 14013342311241.
It is a super-2 number, since 2×1421132433104102 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1378631251 + ... + 1378734329.
It is an arithmetic number, because the mean of its divisors is an integer number (2802575324160).
Almost surely, 2142113243310410 is an apocalyptic number.
142113243310410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 142113243310410, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (179364820746240).
142113243310410 is an abundant number, since it is smaller than the sum of its proper divisors (216616398182070).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
142113243310410 is a wasteful number, since it uses less digits than its factorization.
142113243310410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 118972.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 142113243310410 its reverse (14013342311241), we get a palindrome (156126585621651).
The spelling of 142113243310410 in words is "one hundred forty-two trillion, one hundred thirteen billion, two hundred forty-three million, three hundred ten thousand, four hundred ten".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.088 sec. • engine limits •