Base | Representation |
---|---|
bin | 10100101011100111010… |
… | …111111001111101111000 |
3 | 12000212102100001212101002 |
4 | 110223213113321331320 |
5 | 141241130034330240 |
6 | 3004522214344132 |
7 | 204452116162505 |
oct | 24534727717570 |
9 | 5025370055332 |
10 | 1421221011320 |
11 | 4a8811234180 |
12 | 1ab53805b048 |
13 | a40362517c6 |
14 | 4cb04b304ac |
15 | 26e811b6d15 |
hex | 14ae75f9f78 |
1421221011320 has 128 divisors (see below), whose sum is σ = 3821022590400. Its totient is φ = 469634457600.
The previous prime is 1421221011313. The next prime is 1421221011347. The reversal of 1421221011320 is 231101221241.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 1421221011292 and 1421221011301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3058991 + ... + 3492830.
Almost surely, 21421221011320 is an apocalyptic number.
1421221011320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1421221011320 is an abundant number, since it is smaller than the sum of its proper divisors (2399801579080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1421221011320 is a wasteful number, since it uses less digits than its factorization.
1421221011320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6551889 (or 6551885 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 1421221011320 its reverse (231101221241), we get a palindrome (1652322232561).
The spelling of 1421221011320 in words is "one trillion, four hundred twenty-one billion, two hundred twenty-one million, eleven thousand, three hundred twenty".
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