Base | Representation |
---|---|
bin | 11010011111001010… |
… | …00010011100100100 |
3 | 1100201000110102100012 |
4 | 31033211002130210 |
5 | 213110310330200 |
6 | 10311012105352 |
7 | 1012246046615 |
oct | 151745023444 |
9 | 40630412305 |
10 | 14220011300 |
11 | 6037909a60 |
12 | 290a305258 |
13 | 1458081791 |
14 | 98c7c7c0c |
15 | 5835e1a35 |
hex | 34f942724 |
14220011300 has 72 divisors (see below), whose sum is σ = 34297929792. Its totient is φ = 5073328000.
The previous prime is 14220011287. The next prime is 14220011357. The reversal of 14220011300 is 311002241.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 63656 + ... + 180255.
It is an arithmetic number, because the mean of its divisors is an integer number (476360136).
Almost surely, 214220011300 is an apocalyptic number.
14220011300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14220011300 is an abundant number, since it is smaller than the sum of its proper divisors (20077918492).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14220011300 is a wasteful number, since it uses less digits than its factorization.
14220011300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 243989 (or 243982 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 14220011300 its reverse (311002241), we get a palindrome (14531013541).
The spelling of 14220011300 in words is "fourteen billion, two hundred twenty million, eleven thousand, three hundred".
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