1422050333 has 4 divisors (see below), whose sum is σ = 1551327648. Its totient is φ = 1292773020.

The previous prime is 1422050327. The next prime is 1422050339. The reversal of 1422050333 is 3330502241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3330502241 = 11 ⋅302772931.

It is an interprime number because it is at equal distance from previous prime (1422050327) and next prime (1422050339).

It is not a de Polignac number, because 1422050333 - 2⁴ = 1422050317 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1422050299 and 1422050308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1422050339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64638641 + ... + 64638662.

It is an arithmetic number, because the mean of its divisors is an integer number (387831912).

Almost surely, 2^1422050333 is an apocalyptic number.

It is an amenable number.

1422050333 is a deficient number, since it is larger than the sum of its proper divisors (129277315).

1422050333 is a wasteful number, since it uses less digits than its factorization.

1422050333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 129277314.

The product of its (nonzero) digits is 2160, while the sum is 23.

The square root of 1422050333 is about 37710.0826437705. The cubic root of 1422050333 is about 1124.5315799359.

Adding to 1422050333 its reverse (3330502241), we get a palindrome (4752552574).

The spelling of 1422050333 in words is "one billion, four hundred twenty-two million, fifty thousand, three hundred thirty-three".