Base | Representation |
---|---|
bin | 1100111101000011101110… |
… | …1001101101011101101000 |
3 | 1212102121221222200121021012 |
4 | 3033100323221231131220 |
5 | 3331324343224442100 |
6 | 50143110120203052 |
7 | 3000013413232613 |
oct | 317207351553550 |
9 | 55377858617235 |
10 | 14243112343400 |
11 | 45a1519667556 |
12 | 17204b1609488 |
13 | 7c4173082a95 |
14 | 37352820917a |
15 | 19a7691e0135 |
hex | cf43ba6d768 |
14243112343400 has 48 divisors (see below), whose sum is σ = 33197818021740. Its totient is φ = 5683037312000.
The previous prime is 14243112343393. The next prime is 14243112343529. The reversal of 14243112343400 is 434321134241.
It can be written as a sum of positive squares in 6 ways, for example, as 8135581062436 + 6107531280964 = 2852294^2 + 2471342^2 .
It is a super-3 number, since 3×142431123434003 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 88717259 + ... + 88877658.
Almost surely, 214243112343400 is an apocalyptic number.
14243112343400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14243112343400 is an abundant number, since it is smaller than the sum of its proper divisors (18954705678340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14243112343400 is a wasteful number, since it uses less digits than its factorization.
14243112343400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 177595334 (or 177595325 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 14243112343400 its reverse (434321134241), we get a palindrome (14677433477641).
The spelling of 14243112343400 in words is "fourteen trillion, two hundred forty-three billion, one hundred twelve million, three hundred forty-three thousand, four hundred".
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