Base | Representation |
---|---|
bin | 10100101111001111010… |
… | …111100000010101010011 |
3 | 12001020110120221120112020 |
4 | 110233033113200111103 |
5 | 141322112441023220 |
6 | 3010404334102523 |
7 | 204650430335112 |
oct | 24571727402523 |
9 | 5036416846466 |
10 | 1425113220435 |
11 | 4aa429295523 |
12 | 1b024364aa43 |
13 | a4506732518 |
14 | 4cd93a25c79 |
15 | 2710cc49040 |
hex | 14bcf5e0553 |
1425113220435 has 64 divisors (see below), whose sum is σ = 2362324124160. Its totient is φ = 733129989120.
The previous prime is 1425113220397. The next prime is 1425113220451. The reversal of 1425113220435 is 5340223115241.
It is not a de Polignac number, because 1425113220435 - 29 = 1425113219923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1425113220396 and 1425113220405.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 31282584 + ... + 31328106.
It is an arithmetic number, because the mean of its divisors is an integer number (36911314440).
Almost surely, 21425113220435 is an apocalyptic number.
1425113220435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1425113220435 is a deficient number, since it is larger than the sum of its proper divisors (937210903725).
1425113220435 is a wasteful number, since it uses less digits than its factorization.
1425113220435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46148.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 1425113220435 its reverse (5340223115241), we get a palindrome (6765336335676).
The spelling of 1425113220435 in words is "one trillion, four hundred twenty-five billion, one hundred thirteen million, two hundred twenty thousand, four hundred thirty-five".
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