Base | Representation |
---|---|
bin | 11010101010001000… |
… | …10110000111010000 |
3 | 1100221102202020022202 |
4 | 31111010112013100 |
5 | 213302344320100 |
6 | 10324102022332 |
7 | 1014444610616 |
oct | 152504260720 |
9 | 40842666282 |
10 | 14312104400 |
11 | 608489a960 |
12 | 29351179a8 |
13 | 1471187339 |
14 | 99ab1b6b6 |
15 | 58b7337d5 |
hex | 3551161d0 |
14312104400 has 120 divisors (see below), whose sum is σ = 37720064928. Its totient is φ = 5175360000.
The previous prime is 14312104357. The next prime is 14312104403. The reversal of 14312104400 is 440121341.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14312104403) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 787415 + ... + 805385.
Almost surely, 214312104400 is an apocalyptic number.
14312104400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 14312104400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18860032464).
14312104400 is an abundant number, since it is smaller than the sum of its proper divisors (23407960528).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14312104400 is a wasteful number, since it uses less digits than its factorization.
14312104400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18181 (or 18170 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 14312104400 its reverse (440121341), we get a palindrome (14752225741).
The spelling of 14312104400 in words is "fourteen billion, three hundred twelve million, one hundred four thousand, four hundred".
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