Base | Representation |
---|---|
bin | 10100110100111010111… |
… | …001011001010110011100 |
3 | 12001211012122022120110201 |
4 | 110310322321121112130 |
5 | 141422110312443030 |
6 | 3013253445113244 |
7 | 205254526160143 |
oct | 24647271312634 |
9 | 5054178276421 |
10 | 1431212234140 |
11 | 501a78aa3817 |
12 | 1b14660b8824 |
13 | a4c69187b80 |
14 | 4d3b1a4a75a |
15 | 273683de2ca |
hex | 14d3ae5959c |
1431212234140 has 48 divisors (see below), whose sum is σ = 3237158298528. Its totient is φ = 528379547904.
The previous prime is 1431212234131. The next prime is 1431212234189. The reversal of 1431212234140 is 414322121341.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 1431212234099 and 1431212234108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1691299 + ... + 2392261.
It is an arithmetic number, because the mean of its divisors is an integer number (67440797886).
Almost surely, 21431212234140 is an apocalyptic number.
1431212234140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1431212234140 is an abundant number, since it is smaller than the sum of its proper divisors (1805946064388).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1431212234140 is a wasteful number, since it uses less digits than its factorization.
1431212234140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 708838 (or 708836 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 1431212234140 its reverse (414322121341), we get a palindrome (1845534355481).
The spelling of 1431212234140 in words is "one trillion, four hundred thirty-one billion, two hundred twelve million, two hundred thirty-four thousand, one hundred forty".
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