143130011232 has 48 divisors (see below), whose sum is σ = 404617535280. Its totient is φ = 44040003072.

The previous prime is 143130011209. The next prime is 143130011237. The reversal of 143130011232 is 232110031341.

It is a tau number, because it is divible by the number of its divisors (48).

It is a junction number, because it is equal to n+sod(n) for n = 143130011199 and 143130011208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143130011237) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57342507 + ... + 57345002.

It is an arithmetic number, because the mean of its divisors is an integer number (8429531985).

Almost surely, 2^143130011232 is an apocalyptic number.

143130011232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

143130011232 is an abundant number, since it is smaller than the sum of its proper divisors (261487524048).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143130011232 is a wasteful number, since it uses less digits than its factorization.

143130011232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 114687535 (or 114687527 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 143130011232 its reverse (232110031341), we get a palindrome (375240042573).

The spelling of 143130011232 in words is "one hundred forty-three billion, one hundred thirty million, eleven thousand, two hundred thirty-two".