143130101122120 has 96 divisors (see below), whose sum is σ = 383333251593600. Its totient is φ = 47931940812672.

The previous prime is 143130101122111. The next prime is 143130101122147. The reversal of 143130101122120 is 21221101031341.

143130101122120 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 143130101122091 and 143130101122100.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 849050160 + ... + 849218719.

It is an arithmetic number, because the mean of its divisors is an integer number (3993054704100).

Almost surely, 2^{143130101122120} is an apocalyptic number.

143130101122120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

143130101122120 is an abundant number, since it is smaller than the sum of its proper divisors (240203150471480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143130101122120 is a wasteful number, since it uses less digits than its factorization.

143130101122120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1698268947 (or 1698268936 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 143130101122120 its reverse (21221101031341), we get a palindrome (164351202153461).

The spelling of 143130101122120 in words is "one hundred forty-three trillion, one hundred thirty billion, one hundred one million, one hundred twenty-two thousand, one hundred twenty".