Base | Representation |
---|---|
bin | 1101000001001100100110… |
… | …0110011010011011111000 |
3 | 1212200102111010201110201012 |
4 | 3100103021212122123320 |
5 | 3334011002102223230 |
6 | 50235505301013052 |
7 | 3005111356455065 |
oct | 320231146323370 |
9 | 55612433643635 |
10 | 14314213320440 |
11 | 4619695280a00 |
12 | 17322350b4188 |
13 | 7caa94630a27 |
14 | 376b51135c6c |
15 | 19c52b2cb395 |
hex | d04c999a6f8 |
14314213320440 has 48 divisors (see below), whose sum is σ = 35401060641240. Its totient is φ = 5205168478400.
The previous prime is 14314213320439. The next prime is 14314213320443. The reversal of 14314213320440 is 4402331241341.
It is a junction number, because it is equal to n+sod(n) for n = 14314213320397 and 14314213320406.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14314213320443) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1478736206 + ... + 1478745885.
Almost surely, 214314213320440 is an apocalyptic number.
14314213320440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14314213320440 is an abundant number, since it is smaller than the sum of its proper divisors (21086847320800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14314213320440 is a wasteful number, since it uses less digits than its factorization.
14314213320440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2957482124 (or 2957482109 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 14314213320440 its reverse (4402331241341), we get a palindrome (18716544561781).
The spelling of 14314213320440 in words is "fourteen trillion, three hundred fourteen billion, two hundred thirteen million, three hundred twenty thousand, four hundred forty".
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