Base | Representation |
---|---|
bin | 10100110111111011011… |
… | …101110111110000010111 |
3 | 12002010112210121120022201 |
4 | 110313323131313300113 |
5 | 142000214403140320 |
6 | 3014550220105331 |
7 | 205430556334612 |
oct | 24677335676027 |
9 | 5063483546281 |
10 | 1434443021335 |
11 | 503386764a85 |
12 | 1b2008095247 |
13 | a5362615a7c |
14 | 4d5dab6b179 |
15 | 274a6d6e70a |
hex | 14dfb777c17 |
1434443021335 has 8 divisors (see below), whose sum is σ = 1822586427216. Its totient is φ = 1080051216000.
The previous prime is 1434443021317. The next prime is 1434443021339. The reversal of 1434443021335 is 5331203444341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1434443021335 - 29 = 1434443020823 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1434443021294 and 1434443021303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1434443021339) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8437900041 + ... + 8437900210.
It is an arithmetic number, because the mean of its divisors is an integer number (227823303402).
Almost surely, 21434443021335 is an apocalyptic number.
1434443021335 is a deficient number, since it is larger than the sum of its proper divisors (388143405881).
1434443021335 is a wasteful number, since it uses less digits than its factorization.
1434443021335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16875800273.
The product of its (nonzero) digits is 207360, while the sum is 37.
Adding to 1434443021335 its reverse (5331203444341), we get a palindrome (6765646465676).
The spelling of 1434443021335 in words is "one trillion, four hundred thirty-four billion, four hundred forty-three million, twenty-one thousand, three hundred thirty-five".
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