Base | Representation |
---|---|
bin | 100010110100000101110010… |
… | …001000110101000001010010 |
3 | 202002010110221110010202101012 |
4 | 202310011302020311001102 |
5 | 130032101320214131200 |
6 | 1301351122423210522 |
7 | 44152030634445524 |
oct | 4264056210650122 |
9 | 662113843122335 |
10 | 153113204052050 |
11 | 44871a44041850 |
12 | 1520a4462a6a42 |
13 | 67586896229a8 |
14 | 29b4a0bc57a14 |
15 | 12a7c5c1b9a35 |
hex | 8b4172235052 |
153113204052050 has 96 divisors (see below), whose sum is σ = 341251014251520. Its totient is φ = 50453778830400.
The previous prime is 153113204052019. The next prime is 153113204052059. The reversal of 153113204052050 is 50250402311351.
It is a junction number, because it is equal to n+sod(n) for n = 153113204051998 and 153113204052016.
It is not an unprimeable number, because it can be changed into a prime (153113204052059) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 318280982 + ... + 318761681.
It is an arithmetic number, because the mean of its divisors is an integer number (3554698065120).
Almost surely, 2153113204052050 is an apocalyptic number.
153113204052050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
153113204052050 is an abundant number, since it is smaller than the sum of its proper divisors (188137810199470).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
153113204052050 is a wasteful number, since it uses less digits than its factorization.
153113204052050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 637042728 (or 637042723 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 32.
The spelling of 153113204052050 in words is "one hundred fifty-three trillion, one hundred thirteen billion, two hundred four million, fifty-two thousand, fifty".
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