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153134300000 = 2555111719431
BaseRepresentation
bin1000111010011110000…
…0111111101101100000
3112122021012012110011202
42032213200333231200
510002104340100000
6154203211300332
714030545034063
oct2164740775540
9478235173152
10153134300000
1159a42358130
122581844a6a8
1311595a26746
1475a9b568da
153eb3d50dd5
hex23a783fb60

153134300000 has 576 divisors, whose sum is σ = 459240606720. Its totient is φ = 49536000000.

The previous prime is 153134299951. The next prime is 153134300003. The reversal of 153134300000 is 3431351.

It is a happy number.

It is a super-2 number, since 2×1531343000002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (153134300003) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 355299785 + ... + 355300215.

It is an arithmetic number, because the mean of its divisors is an integer number (797292720).

Almost surely, 2153134300000 is an apocalyptic number.

153134300000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 153134300000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (229620303360).

153134300000 is an abundant number, since it is smaller than the sum of its proper divisors (306106306720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

153134300000 is a wasteful number, since it uses less digits than its factorization.

153134300000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 513 (or 485 counting only the distinct ones).

The product of its (nonzero) digits is 540, while the sum is 20.

Adding to 153134300000 its reverse (3431351), we get a palindrome (153137731351).

The spelling of 153134300000 in words is "one hundred fifty-three billion, one hundred thirty-four million, three hundred thousand".