Base | Representation |
---|---|
bin | 10111011000000000011… |
… | …000011000101100010100 |
3 | 12200120012111022011100120 |
4 | 113120000120120230110 |
5 | 202304222441130200 |
6 | 3225533553311540 |
7 | 224024132042055 |
oct | 27300030305424 |
9 | 5616174264316 |
10 | 1606324161300 |
11 | 56a269126481 |
12 | 21b3968655b0 |
13 | b86251cc111 |
14 | 57a6459c72c |
15 | 2bbb68ee9a0 |
hex | 17600618b14 |
1606324161300 has 72 divisors (see below), whose sum is σ = 4695545049216. Its totient is φ = 423937090560.
The previous prime is 1606324161289. The next prime is 1606324161311. The reversal of 1606324161300 is 31614236061.
It is an interprime number because it is at equal distance from previous prime (1606324161289) and next prime (1606324161311).
It is a super-2 number, since 2×16063241613002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 27570972 + ... + 27629171.
Almost surely, 21606324161300 is an apocalyptic number.
1606324161300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1606324161300 is an abundant number, since it is smaller than the sum of its proper divisors (3089220887916).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1606324161300 is a wasteful number, since it uses less digits than its factorization.
1606324161300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55200257 (or 55200250 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 33.
Adding to 1606324161300 its reverse (31614236061), we get a palindrome (1637938397361).
The spelling of 1606324161300 in words is "one trillion, six hundred six billion, three hundred twenty-four million, one hundred sixty-one thousand, three hundred".
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