Base | Representation |
---|---|
bin | 1001110111000110011… |
… | …1001101001110101011 |
3 | 121012021110110221000000 |
4 | 2131301213031032223 |
5 | 10233422403442010 |
6 | 205454212314043 |
7 | 15145063530240 |
oct | 2356147151653 |
9 | 535243427000 |
10 | 169409827755 |
11 | 65934482013 |
12 | 289bb012923 |
13 | 12c8a8bc83c |
14 | 82b152b5c7 |
15 | 4617b1e7c0 |
hex | 27719cd3ab |
169409827755 has 112 divisors (see below), whose sum is σ = 363487380480. Its totient is φ = 74077084224.
The previous prime is 169409827747. The next prime is 169409827781. The reversal of 169409827755 is 557728904961.
It is not a de Polignac number, because 169409827755 - 23 = 169409827747 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (63).
It is a junction number, because it is equal to n+sod(n) for n = 169409827692 and 169409827701.
It is an unprimeable number.
It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 442506 + ... + 731184.
It is an arithmetic number, because the mean of its divisors is an integer number (3245423040).
Almost surely, 2169409827755 is an apocalyptic number.
169409827755 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
169409827755 is an abundant number, since it is smaller than the sum of its proper divisors (194077552725).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
169409827755 is an equidigital number, since it uses as much as digits as its factorization.
169409827755 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 288732 (or 288717 counting only the distinct ones).
The product of its (nonzero) digits is 38102400, while the sum is 63.
The spelling of 169409827755 in words is "one hundred sixty-nine billion, four hundred nine million, eight hundred twenty-seven thousand, seven hundred fifty-five".
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