Base | Representation |
---|---|
bin | 1011010111010001101… |
… | …1000101110000011101 |
3 | 200122220200122100000000 |
4 | 2311310123011300131 |
5 | 11144311024134340 |
6 | 225404055324513 |
7 | 20050621210446 |
oct | 2656433056035 |
9 | 618820570000 |
10 | 195226786845 |
11 | 75882482542 |
12 | 31a05080739 |
13 | 155434661ac |
14 | 96401b62cd |
15 | 51293b8d30 |
hex | 2d746c5c1d |
195226786845 has 72 divisors (see below), whose sum is σ = 351679156920. Its totient is φ = 104035415040.
The previous prime is 195226786709. The next prime is 195226786873. The reversal of 195226786845 is 548687622591.
195226786845 is a `hidden beast` number, since 1 + 9 + 522 + 6 + 7 + 8 + 68 + 45 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 24642092484 + 170584694361 = 156978^2 + 413019^2 .
It is not a de Polignac number, because 195226786845 - 210 = 195226785821 is a prime.
It is a super-2 number, since 2×1952267868452 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 74826901 + ... + 74829509.
It is an arithmetic number, because the mean of its divisors is an integer number (4884432735).
Almost surely, 2195226786845 is an apocalyptic number.
195226786845 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
195226786845 is a deficient number, since it is larger than the sum of its proper divisors (156452370075).
195226786845 is an frugal number, since it uses more digits than its factorization.
195226786845 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4919 (or 4898 counting only the distinct ones).
The product of its digits is 58060800, while the sum is 63.
The spelling of 195226786845 in words is "one hundred ninety-five billion, two hundred twenty-six million, seven hundred eighty-six thousand, eight hundred forty-five".
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