Base | Representation |
---|---|
bin | 1011101001011110101… |
… | …1000001011011110100 |
3 | 201010112020011110012122 |
4 | 2322113223001123310 |
5 | 11234312430231200 |
6 | 231533010535112 |
7 | 20312663365463 |
oct | 2722753013364 |
9 | 633466143178 |
10 | 200113133300 |
11 | 7795a7129a3 |
12 | 32949597498 |
13 | 15b418b0762 |
14 | 99851309da |
15 | 5313370385 |
hex | 2e97ac16f4 |
200113133300 has 72 divisors (see below), whose sum is σ = 435315575520. Its totient is φ = 79848316800.
The previous prime is 200113133273. The next prime is 200113133303. The reversal of 200113133300 is 3331311002.
It is a super-2 number, since 2×2001131333002 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200113133303) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 117092846 + ... + 117094554.
It is an arithmetic number, because the mean of its divisors is an integer number (6046049660).
Almost surely, 2200113133300 is an apocalyptic number.
200113133300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
200113133300 is an abundant number, since it is smaller than the sum of its proper divisors (235202442220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200113133300 is a wasteful number, since it uses less digits than its factorization.
200113133300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3921 (or 3914 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 200113133300 its reverse (3331311002), we get a palindrome (203444444302).
The spelling of 200113133300 in words is "two hundred billion, one hundred thirteen million, one hundred thirty-three thousand, three hundred".
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