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2003130030000 = 243541123412157
BaseRepresentation
bin11101001001100011110…
…110101001011110110000
321002111102120112211221010
4131021203312221132300
5230304402241430000
64132120352230520
7264502300214661
oct35114366513660
97074376484833
102003130030000
11702582753740
1228427823b440
13116b81b74c28
146cd48463368
153718cba8d50
hex1d263da97b0

2003130030000 has 1200 divisors, whose sum is σ = 7592898094848. Its totient is φ = 450278400000.

The previous prime is 2003130029969. The next prime is 2003130030043. The reversal of 2003130030000 is 300313002.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (1200).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 12758789922 + ... + 12758790078.

Almost surely, 22003130030000 is an apocalyptic number.

2003130030000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2003130030000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3796449047424).

2003130030000 is an abundant number, since it is smaller than the sum of its proper divisors (5589768064848).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2003130030000 is a wasteful number, since it uses less digits than its factorization.

2003130030000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 304 (or 242 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 12.

Adding to 2003130030000 its reverse (300313002), we get a palindrome (2003430343002).

The spelling of 2003130030000 in words is "two trillion, three billion, one hundred thirty million, thirty thousand".