Base | Representation |
---|---|
bin | 1001000111000110001001… |
… | …11011001101101010011101 |
3 | 2121221022220210002012212212 |
4 | 10203203010323031222131 |
5 | 10111223221004402331 |
6 | 110335544421010205 |
7 | 4135324516253504 |
oct | 443430473155235 |
9 | 77838823065785 |
10 | 20035031325341 |
11 | 642489996428a |
12 | 22b6b0b553965 |
13 | b243abb54a06 |
14 | 4d39b499d83b |
15 | 24b255552d2b |
hex | 1238c4ecda9d |
20035031325341 has 8 divisors (see below), whose sum is σ = 20415822749400. Its totient is φ = 19655928555840.
The previous prime is 20035031325313. The next prime is 20035031325349. The reversal of 20035031325341 is 14352313053002.
It can be written as a sum of positive squares in 4 ways, for example, as 655921812100 + 19379109513241 = 809890^2 + 4402171^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 20035031325341 - 26 = 20035031325277 is a prime.
It is a super-3 number, since 3×200350313253413 (a number of 41 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20035031325298 and 20035031325307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20035031325349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 422139686 + ... + 422187143.
It is an arithmetic number, because the mean of its divisors is an integer number (2551977843675).
Almost surely, 220035031325341 is an apocalyptic number.
It is an amenable number.
20035031325341 is a deficient number, since it is larger than the sum of its proper divisors (380791424059).
20035031325341 is an equidigital number, since it uses as much as digits as its factorization.
20035031325341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 844327279.
The product of its (nonzero) digits is 32400, while the sum is 32.
Adding to 20035031325341 its reverse (14352313053002), we get a palindrome (34387344378343).
The spelling of 20035031325341 in words is "twenty trillion, thirty-five billion, thirty-one million, three hundred twenty-five thousand, three hundred forty-one".
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