Base | Representation |
---|---|
bin | 1011101101001100110… |
… | …1110111011100000100 |
3 | 201020002211221101122100 |
4 | 2323103031313130010 |
5 | 11243334200420030 |
6 | 232220054432100 |
7 | 20346513561345 |
oct | 2732315673404 |
9 | 636084841570 |
10 | 201112123140 |
11 | 78322606835 |
12 | 32b88062630 |
13 | 15c70855bc6 |
14 | 9a3ba980cc |
15 | 5370e02360 |
hex | 2ed3377704 |
201112123140 has 144 divisors (see below), whose sum is σ = 616807166976. Its totient is φ = 53036256000.
The previous prime is 201112123097. The next prime is 201112123141. The reversal of 201112123140 is 41321211102.
201112123140 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (201112123141) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 16555909 + ... + 16568051.
It is an arithmetic number, because the mean of its divisors is an integer number (4283383104).
Almost surely, 2201112123140 is an apocalyptic number.
201112123140 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 201112123140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (308403583488).
201112123140 is an abundant number, since it is smaller than the sum of its proper divisors (415695043836).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201112123140 is a wasteful number, since it uses less digits than its factorization.
201112123140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13170 (or 13165 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 201112123140 its reverse (41321211102), we get a palindrome (242433334242).
The spelling of 201112123140 in words is "two hundred one billion, one hundred twelve million, one hundred twenty-three thousand, one hundred forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •