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201201121111 is a prime number
BaseRepresentation
bin1011101101100010000…
…1010111011101010111
3201020100001101221220111
42323120201113131113
511244024441333421
6232232554143451
720351644211554
oct2733041273527
9636301357814
10201201121111
1178368873281
1232bb1a21b87
1315c86116a23
149a49823a2b
155378b31ee1
hex2ed8857757

201201121111 has 2 divisors, whose sum is σ = 201201121112. Its totient is φ = 201201121110.

The previous prime is 201201121109. The next prime is 201201121123. The reversal of 201201121111 is 111121102102.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 201201121111 - 21 = 201201121109 is a prime.

It is a super-2 number, since 2×2012011211112 (a number of 23 digits) contains 22 as substring.

Together with 201201121109, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 201201121091 and 201201121100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201201128111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100600560555 + 100600560556.

It is an arithmetic number, because the mean of its divisors is an integer number (100600560556).

Almost surely, 2201201121111 is an apocalyptic number.

201201121111 is a deficient number, since it is larger than the sum of its proper divisors (1).

201201121111 is an equidigital number, since it uses as much as digits as its factorization.

201201121111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 201201121111 its reverse (111121102102), we get a palindrome (312322223213).

The spelling of 201201121111 in words is "two hundred one billion, two hundred one million, one hundred twenty-one thousand, one hundred eleven".