Base | Representation |
---|---|
bin | 101111111110101000010111… |
… | …000111001011110110101100 |
3 | 1000200010120012012220222221000 |
4 | 233332220113013023312230 |
5 | 210124210321014341022 |
6 | 2024441345034440300 |
7 | 62306060213432121 |
oct | 5776502707136654 |
9 | 1020116165828830 |
10 | 211012131012012 |
11 | 61264818977120 |
12 | 1b7bb693893090 |
13 | 9098487a28a45 |
14 | 3a1708235c748 |
15 | 195dd9a7476ac |
hex | bfea171cbdac |
211012131012012 has 96 divisors (see below), whose sum is σ = 606585626035200. Its totient is φ = 62894822932800.
The previous prime is 211012131011999. The next prime is 211012131012031. The reversal of 211012131012012 is 210210131210112.
It is a happy number.
211012131012012 is a `hidden beast` number, since 2 + 110 + 121 + 310 + 120 + 1 + 2 = 666.
It is a super-2 number, since 2×2110121310120122 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1455826212 + ... + 1455971147.
It is an arithmetic number, because the mean of its divisors is an integer number (6318600271200).
Almost surely, 2211012131012012 is an apocalyptic number.
211012131012012 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
It is an amenable number.
211012131012012 is an abundant number, since it is smaller than the sum of its proper divisors (395573495023188).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211012131012012 is a wasteful number, since it uses less digits than its factorization.
211012131012012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2911797444 (or 2911797436 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 18.
Adding to 211012131012012 its reverse (210210131210112), we get a palindrome (421222262222124).
It can be divided in two parts, 2110121 and 31012012, that added together give a palindrome (33122133).
The spelling of 211012131012012 in words is "two hundred eleven trillion, twelve billion, one hundred thirty-one million, twelve thousand, twelve".
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