Base | Representation |
---|---|
bin | 11110101110011010000… |
… | …110000001101000000000 |
3 | 21110211221002100022000212 |
4 | 132232122012001220000 |
5 | 234043134014304440 |
6 | 4253545330133252 |
7 | 305354545455602 |
oct | 36563206015000 |
9 | 7424832308025 |
10 | 2111414213120 |
11 | 74449a308173 |
12 | 2a1258421228 |
13 | 12414aa48174 |
14 | 7429b805172 |
15 | 39dc9326465 |
hex | 1eb9a181a00 |
2111414213120 has 40 divisors (see below), whose sum is σ = 5062445490564. Its totient is φ = 844565684224.
The previous prime is 2111414213101. The next prime is 2111414213137. The reversal of 2111414213120 is 213124141112.
It can be written as a sum of positive squares in 2 ways, for example, as 1952704401664 + 158709811456 = 1397392^2 + 398384^2 .
It is a tau number, because it is divible by the number of its divisors (40).
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 412383029 + ... + 412388148.
Almost surely, 22111414213120 is an apocalyptic number.
2111414213120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2111414213120 is an abundant number, since it is smaller than the sum of its proper divisors (2951031277444).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2111414213120 is an frugal number, since it uses more digits than its factorization.
2111414213120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 824771200 (or 824771184 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 2111414213120 its reverse (213124141112), we get a palindrome (2324538354232).
The spelling of 2111414213120 in words is "two trillion, one hundred eleven billion, four hundred fourteen million, two hundred thirteen thousand, one hundred twenty".
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