Base | Representation |
---|---|
bin | 1100010100001011011… |
… | …0101110111010100100 |
3 | 202020010000202201122120 |
4 | 3011002312232322210 |
5 | 11431301202313300 |
6 | 241110215225540 |
7 | 21200012116161 |
oct | 3050266567244 |
9 | 666100681576 |
10 | 211575041700 |
11 | 81801660370 |
12 | 350080782b0 |
13 | 16c4a414189 |
14 | a3514bd068 |
15 | 57847513a0 |
hex | 3142daeea4 |
211575041700 has 72 divisors (see below), whose sum is σ = 667807778400. Its totient is φ = 51290918400.
The previous prime is 211575041663. The next prime is 211575041729. The reversal of 211575041700 is 7140575112.
211575041700 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-4 number, since 4×2115750417004 (a number of 46 digits) contains 4444 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 32053525 + ... + 32060124.
Almost surely, 2211575041700 is an apocalyptic number.
211575041700 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211575041700 is an abundant number, since it is smaller than the sum of its proper divisors (456232736700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211575041700 is a wasteful number, since it uses less digits than its factorization.
211575041700 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 64113677 (or 64113670 counting only the distinct ones).
The product of its (nonzero) digits is 9800, while the sum is 33.
The spelling of 211575041700 in words is "two hundred eleven billion, five hundred seventy-five million, forty-one thousand, seven hundred".
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