Base | Representation |
---|---|
bin | 1100011001111001101… |
… | …1100101111111010000 |
3 | 202101002002202101201102 |
4 | 3012132123211333100 |
5 | 11442423011243440 |
6 | 241522501323532 |
7 | 21253046163500 |
oct | 3063633457720 |
9 | 671062671642 |
10 | 213111431120 |
11 | 8241a935495 |
12 | 353767065a8 |
13 | 17133807743 |
14 | a459575a00 |
15 | 5824587b15 |
hex | 319e6e5fd0 |
213111431120 has 60 divisors (see below), whose sum is σ = 576379447524. Its totient is φ = 73066775040.
The previous prime is 213111431107. The next prime is 213111431161. The reversal of 213111431120 is 21134111312.
It can be written as a sum of positive squares in 2 ways, for example, as 54557747776 + 158553683344 = 233576^2 + 398188^2 .
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 213111431092 and 213111431101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 27178661 + ... + 27186500.
Almost surely, 2213111431120 is an apocalyptic number.
213111431120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
213111431120 is an abundant number, since it is smaller than the sum of its proper divisors (363268016404).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213111431120 is a wasteful number, since it uses less digits than its factorization.
213111431120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54365188 (or 54365175 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 213111431120 its reverse (21134111312), we get a palindrome (234245542432).
The spelling of 213111431120 in words is "two hundred thirteen billion, one hundred eleven million, four hundred thirty-one thousand, one hundred twenty".
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