Base | Representation |
---|---|
bin | 11111000000110001010… |
… | …011101001000000111010 |
3 | 21112201211011222102012000 |
4 | 133000301103221000322 |
5 | 234404024014324010 |
6 | 4311010021401430 |
7 | 306653261464662 |
oct | 37006123510072 |
9 | 7481734872160 |
10 | 2131131011130 |
11 | 751897996360 |
12 | 2a503b569276 |
13 | 125c70856b54 |
14 | 7520c24b1a2 |
15 | 3a6802a07c0 |
hex | 1f0314e903a |
2131131011130 has 64 divisors (see below), whose sum is σ = 6199653859200. Its totient is φ = 516637820160.
The previous prime is 2131131011111. The next prime is 2131131011143. The reversal of 2131131011130 is 311101311312.
2131131011130 is a `hidden beast` number, since 2 + 1 + 311 + 310 + 1 + 11 + 30 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 358773295 + ... + 358779234.
It is an arithmetic number, because the mean of its divisors is an integer number (96869591550).
Almost surely, 22131131011130 is an apocalyptic number.
2131131011130 is an abundant number, since it is smaller than the sum of its proper divisors (4068522848070).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2131131011130 is a wasteful number, since it uses less digits than its factorization.
2131131011130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 717552556 (or 717552550 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 2131131011130 its reverse (311101311312), we get a palindrome (2442232322442).
The spelling of 2131131011130 in words is "two trillion, one hundred thirty-one billion, one hundred thirty-one million, eleven thousand, one hundred thirty".
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