Base | Representation |
---|---|
bin | 1001101100100101011001… |
… | …00001100000001111010100 |
3 | 2210111110200100100100222111 |
4 | 10312102230201200033110 |
5 | 10243324213200340200 |
6 | 113203411422440404 |
7 | 4330354411341163 |
oct | 466225441401724 |
9 | 83443610310874 |
10 | 21323112121300 |
11 | 688109899a020 |
12 | 248468b133104 |
13 | bb89b77660a2 |
14 | 53a08915d3da |
15 | 26e9e2d670ba |
hex | 1364ac8603d4 |
21323112121300 has 72 divisors (see below), whose sum is σ = 50478855521472. Its totient is φ = 7753669440000.
The previous prime is 21323112121271. The next prime is 21323112121313. The reversal of 21323112121300 is 312121132312.
It is a super-2 number, since 2×213231121213002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 49542025 + ... + 49970575.
It is an arithmetic number, because the mean of its divisors is an integer number (701095215576).
Almost surely, 221323112121300 is an apocalyptic number.
21323112121300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
21323112121300 is an abundant number, since it is smaller than the sum of its proper divisors (29155743400172).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21323112121300 is a wasteful number, since it uses less digits than its factorization.
21323112121300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 473809 (or 473802 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 21323112121300 its reverse (312121132312), we get a palindrome (21635233253612).
It can be divided in two parts, 21323112 and 121300, that added together give a palindrome (21444412).
The spelling of 21323112121300 in words is "twenty-one trillion, three hundred twenty-three billion, one hundred twelve million, one hundred twenty-one thousand, three hundred".
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