Base | Representation |
---|---|
bin | 1001101110110111000011… |
… | …01110100001111101010000 |
3 | 2210202221112101020112021212 |
4 | 10313123201232201331100 |
5 | 10301114342404434414 |
6 | 113303343351235252 |
7 | 4336123341463562 |
oct | 467334156417520 |
9 | 83687471215255 |
10 | 21401314139984 |
11 | 69012789a0129 |
12 | 2497874978b28 |
13 | bc319b23691c |
14 | 53db871c9332 |
15 | 271a6d57a83e |
hex | 1376e1ba1f50 |
21401314139984 has 40 divisors (see below), whose sum is σ = 43834745111040. Its totient is φ = 10093956127488.
The previous prime is 21401314139969. The next prime is 21401314140113. The reversal of 21401314139984 is 48993141310412.
It is a super-3 number, since 3×214013141399843 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 151000112 + ... + 151141775.
It is an arithmetic number, because the mean of its divisors is an integer number (1095868627776).
Almost surely, 221401314139984 is an apocalyptic number.
It is an amenable number.
21401314139984 is an abundant number, since it is smaller than the sum of its proper divisors (22433430971056).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21401314139984 is a wasteful number, since it uses less digits than its factorization.
21401314139984 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 302142147 (or 302142141 counting only the distinct ones).
The product of its (nonzero) digits is 746496, while the sum is 50.
The spelling of 21401314139984 in words is "twenty-one trillion, four hundred one billion, three hundred fourteen million, one hundred thirty-nine thousand, nine hundred eighty-four".
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