Base | Representation |
---|---|
bin | 11111010101010110110… |
… | …001011001001011000011 |
3 | 21121211212121102010001200 |
4 | 133111112301121023003 |
5 | 240234311001412120 |
6 | 4325103210032243 |
7 | 311365104306501 |
oct | 37252661311303 |
9 | 7554777363050 |
10 | 2153234404035 |
11 | 7601aa760620 |
12 | 2a9389a18683 |
13 | 128083c39a70 |
14 | 76307a23671 |
15 | 3b025a03e90 |
hex | 1f556c592c3 |
2153234404035 has 48 divisors (see below), whose sum is σ = 4384768254048. Its totient is φ = 963685324800.
The previous prime is 2153234404019. The next prime is 2153234404091. The reversal of 2153234404035 is 5304044323512.
2153234404035 is a `hidden beast` number, since 2 + 15 + 3 + 234 + 4 + 0 + 403 + 5 = 666.
It is not a de Polignac number, because 2153234404035 - 24 = 2153234404019 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 167300046 + ... + 167312915.
It is an arithmetic number, because the mean of its divisors is an integer number (91349338626).
Almost surely, 22153234404035 is an apocalyptic number.
2153234404035 is an abundant number, since it is smaller than the sum of its proper divisors (2231533850013).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2153234404035 is a wasteful number, since it uses less digits than its factorization.
2153234404035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 334612996 (or 334612993 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 36.
Adding to 2153234404035 its reverse (5304044323512), we get a palindrome (7457278727547).
The spelling of 2153234404035 in words is "two trillion, one hundred fifty-three billion, two hundred thirty-four million, four hundred four thousand, thirty-five".
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