Base | Representation |
---|---|
bin | 1100110011100111100… |
… | …0010101011110101111 |
3 | 210000220011220121211101 |
4 | 3030321320111132233 |
5 | 12101042141321310 |
6 | 245023452103531 |
7 | 21616106361442 |
oct | 3147170253657 |
9 | 700804817741 |
10 | 220014401455 |
11 | 85342437252 |
12 | 36782464ba7 |
13 | 17993999b84 |
14 | a912275659 |
15 | 5aca5d743a |
hex | 3339e157af |
220014401455 has 8 divisors (see below), whose sum is σ = 279547710192. Its totient is φ = 165657902208.
The previous prime is 220014401437. The next prime is 220014401483. The reversal of 220014401455 is 554104410022.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 220014401455 - 223 = 220006012847 is a prime.
It is a super-2 number, since 2×2200144014552 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1294202277 + ... + 1294202446.
It is an arithmetic number, because the mean of its divisors is an integer number (34943463774).
Almost surely, 2220014401455 is an apocalyptic number.
220014401455 is a deficient number, since it is larger than the sum of its proper divisors (59533308737).
220014401455 is a wasteful number, since it uses less digits than its factorization.
220014401455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2588404745.
The product of its (nonzero) digits is 6400, while the sum is 28.
Adding to 220014401455 its reverse (554104410022), we get a palindrome (774118811477).
The spelling of 220014401455 in words is "two hundred twenty billion, fourteen million, four hundred one thousand, four hundred fifty-five".
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