Base | Representation |
---|---|
bin | 1101011110000010001… |
… | …0001000111010000111 |
3 | 211010021200111211102210 |
4 | 3113200202020322013 |
5 | 12242401434444310 |
6 | 254145343434503 |
7 | 22501213126314 |
oct | 3274042107207 |
9 | 733250454383 |
10 | 231400312455 |
11 | 8a155497754 |
12 | 38a1b5b5a33 |
13 | 18a89842010 |
14 | b2b24bdd0b |
15 | 6044ea5820 |
hex | 35e0888e87 |
231400312455 has 32 divisors (see below), whose sum is σ = 398852846784. Its totient is φ = 113882351616.
The previous prime is 231400312439. The next prime is 231400312457. The reversal of 231400312455 is 554213004132.
It is not a de Polignac number, because 231400312455 - 24 = 231400312439 is a prime.
It is a super-2 number, since 2×2314003124552 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (231400312457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 396847 + ... + 787583.
It is an arithmetic number, because the mean of its divisors is an integer number (12464151462).
Almost surely, 2231400312455 is an apocalyptic number.
231400312455 is a deficient number, since it is larger than the sum of its proper divisors (167452534329).
231400312455 is a wasteful number, since it uses less digits than its factorization.
231400312455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 393795.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 231400312455 its reverse (554213004132), we get a palindrome (785613316587).
The spelling of 231400312455 in words is "two hundred thirty-one billion, four hundred million, three hundred twelve thousand, four hundred fifty-five".
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