Base | Representation |
---|---|
bin | 100100100100011010101… |
… | …101100111010001111000 |
3 | 22220020111120102220002210 |
4 | 210210122231213101320 |
5 | 312133113013030034 |
6 | 5202242541455120 |
7 | 346362403560453 |
oct | 44443255472170 |
9 | 8806446386083 |
10 | 2513004033144 |
11 | 889839298910 |
12 | 347053b714a0 |
13 | 152c8a8667c7 |
14 | 898b6bac49a |
15 | 455805ac8e9 |
hex | 2491ab67478 |
2513004033144 has 32 divisors (see below), whose sum is σ = 6853647363840. Its totient is φ = 761516373600.
The previous prime is 2513004033061. The next prime is 2513004033149. The reversal of 2513004033144 is 4413304003152.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2513004033149) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4759477072 + ... + 4759477599.
It is an arithmetic number, because the mean of its divisors is an integer number (214176480120).
Almost surely, 22513004033144 is an apocalyptic number.
2513004033144 is a gapful number since it is divisible by the number (24) formed by its first and last digit.
It is an amenable number.
2513004033144 is an abundant number, since it is smaller than the sum of its proper divisors (4340643330696).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2513004033144 is a wasteful number, since it uses less digits than its factorization.
2513004033144 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9518954691 (or 9518954687 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 30.
Adding to 2513004033144 its reverse (4413304003152), we get a palindrome (6926308036296).
The spelling of 2513004033144 in words is "two trillion, five hundred thirteen billion, four million, thirty-three thousand, one hundred forty-four".
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