Base | Representation |
---|---|
bin | 100100100100101000010… |
… | …100100100101110110111 |
3 | 22220021002111001121010122 |
4 | 210210220110210232313 |
5 | 312134044440201020 |
6 | 5202321335242155 |
7 | 346401145333613 |
oct | 44445024445667 |
9 | 8807074047118 |
10 | 2513232350135 |
11 | 889946161841 |
12 | 3470b851935b |
13 | 152cc5c56a10 |
14 | 898d9242343 |
15 | 4559565c125 |
hex | 24928524bb7 |
2513232350135 has 96 divisors (see below), whose sum is σ = 3435415260480. Its totient is φ = 1754303975424.
The previous prime is 2513232350119. The next prime is 2513232350147. The reversal of 2513232350135 is 5310532323152.
It is not a de Polignac number, because 2513232350135 - 24 = 2513232350119 is a prime.
It is a super-4 number, since 4×25132323501354 (a number of 51 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2513232350095 and 2513232350104.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 2490814511 + ... + 2490815519.
It is an arithmetic number, because the mean of its divisors is an integer number (35785575630).
Almost surely, 22513232350135 is an apocalyptic number.
2513232350135 is a deficient number, since it is larger than the sum of its proper divisors (922182910345).
2513232350135 is a wasteful number, since it uses less digits than its factorization.
2513232350135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1857 (or 1834 counting only the distinct ones).
The product of its (nonzero) digits is 81000, while the sum is 35.
Adding to 2513232350135 its reverse (5310532323152), we get a palindrome (7823764673287).
The spelling of 2513232350135 in words is "two trillion, five hundred thirteen billion, two hundred thirty-two million, three hundred fifty thousand, one hundred thirty-five".
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