31103117 has 2 divisors, whose sum is σ = 31103118. Its totient is φ = 31103116.

The previous prime is 31103099. The next prime is 31103119. The reversal of 31103117 is 71130113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27237961 + 3865156 = 5219^2 + 1966^2 .

It is an emirp because it is prime and its reverse (71130113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31103117 - 2⁶ = 31103053 is a prime.

Together with 31103119, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 31103095 and 31103104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31103119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15551558 + 15551559.

It is an arithmetic number, because the mean of its divisors is an integer number (15551559).

Almost surely, 2^31103117 is an apocalyptic number.

It is an amenable number.

31103117 is a deficient number, since it is larger than the sum of its proper divisors (1).

31103117 is an equidigital number, since it uses as much as digits as its factorization.

31103117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63, while the sum is 17.

The square root of 31103117 is about 5577.0168549145. The cubic root of 31103117 is about 314.4859913064.

The spelling of 31103117 in words is "thirty-one million, one hundred three thousand, one hundred seventeen".